Mass Energy in Pythagoras formula ©

.                                          Mass Energy in Pythagoras formula ©

                                                                    Sree Debasish Dasgupta

 

 

 

 

Abstract:

In my view is every particle and atom and Neutron create up four subjects, these four subjects are Time, space, Energy, and magnetic field. In this article, Each subject (Time, space, energy, etc.) follows Pythagoras formula (a)^{^2} + (b)^{^2} = C^{^2},

 the calculation shown how the values obtained from each section comply with the Pythagoras formula (a)^{^2} + (b)^{^2} = C^{^2},

Here Total energy in Square, ‘a’ & ‘b’ =1.60217653 x 10^{^-19}  Unit.  and ‘C’ = 1.60217653 x 10^{^-19}  Unit.

Because ‘C’ = (a) + (b). as per my view ‘X’ = electrical magnetic field, it’s total value 432 Unit.

‘Y’ = Time, Value = 3600 Unit. ‘Z’ = space, Value 360 Unit.

Some of clue have been made in favor the information giving in the previous article,

[Like, energy = mass – (mass/10)]  

 

Introduction:

This article discusses Pythagoras formula and atomic mass, energy, Neutron etc. in the present article equal  56 Triangles are drown in a hexagon. This hexagon is located in a circle. Three numbers of quadrilaterals (Square, ‘a’ & ‘b’ and ‘C’) are drown in it. ‘a’ & ‘b’ quadrilaterals (equal Square,) is divided into 8 triangles. And ‘C’ is (8+8) = 16 triangles. Total triangle in Square, ‘a’ & ‘b’ and ‘C’ are (8+8+16) = 32 number.

Each quadrilaterals (Square, ‘a’ & ‘b’ and ‘C’) follows Pythagoras formula (a)^{^2} + (b)^{^2} = C^{^2},

Triangles located outside these three quadrilaterals (Square,) ‘a’ & ‘b’ and ‘C’, (56 – 32) = 24 numbers triangles are further divided into 3 part, (‘X’ ‘Y’ ‘Z’ each part 8 numbers triangle)

Which in shown in image (bellow).

 

 1.

We know that proton – mass – energy – equivalent = Proton = 1.503277484 x 10^{^-10} joule,

Newton = 1.503277484 x 10^{^-10} joule,

1.503277484 x 10^{^-10}, meter^{^2} kilogram / second^{^2}

+/- 6.6 x 10^{^-18} joule. Length^{^2} x mass x time^{^-2} , 1.503277484 x 10^{^-10} Joule

Neutron mass = 1.6749 x 10^{^-27} Kg, Proton mass = 1.672623 x 10^{^-27} Kg.

Electron mass = 9.109390 x 10^{^-31} Kg. or 9.109390e-31

Energy of Electron =  -1.60217653 x 10^{^-19}  Unit.

Energy of Proton = +1.60217653 x  10^{^-19} Unit. 

As per e=mC^{^2}

When energy = 1.60217653e-19 Unit in that moment Mass = 1.782662 x 10^{^-36} Unit

(1.60217653 x  10^{^-19}  / 1.782662 x 10^{^-36} )  = 8.9875512015177302259205614973562e+16  = C^{^2}

 As per this view

One Proton energy = 1.672623 x 10^{^-27} x 8.9875512015177302259205614973562e+16 

= 1.5032784853336190483669927333392 x 10^{^-10} Unit

Electron Energy = (1.6021766e-19 / 1.782662e-36) * 9.10939e-31 or -

9.109390 x 10^{^-31} x 8.9875512015177302259205614973562e+16  

= 8.1871109039593596542698503698402e-14  Unit .

[But we know one electron energy = ( -1.60217653e-19 ) Unit and Proton’s energy = ,

 ( + 1.60217653e-19 ) Unit ]

According to the value obtained form the above calculation,

the amount of this energy is hidden inside the Pythagoras formula (a)^{^2} + (b)^{^2} = C^{^2},

 

 In this article total Calculation (Energy = 1.60217653e-19 Unit, Mass = 1.782662e-36 Unit)

And (mass = 1.672623e-27 Unit Proton mass & energy = 1.5032784196545335010226279575152e-10 Unit )

   1/1                                                          As per e=mC^{^2}

 Relation between  ( Energy = 1.60217653e-19 Unit, --  Mass= 1.782662e-36 Unit)

And (Proton energy = 1.5032784196545335010226279575152e-10 Unit,  mass = 1.672623e-27 Unit)

(A) – ( Energy x Mass ) 1.60217653e-19 * 1.782662e-36 = 2.85613921732286e-55 --- (a)

(B) – ( energy x mass ) 

1.5032784196545335010226279575152e-10 * 1.672623e-27 =

2.5144180601178247880809710421829e-37 --- (b)

  (a) / (b) = 2.85613921732286e-55 / 2.5144180601178247880809710421829e-37

= 1.1359046701999198466437634247209e-18  ---- (Ia) [source will be discuss in this article]

 

[ (a) x (b) = 2.5144180601178247880809710421829e-37 * 2.85613921732286e-55

= 7.1815280302473880328624164760998e-92

7.1815280302473880328624164760998e-92 * 9.01^{^64}  = 9.0908288719008089524361213634111e-31

Electron mass.

(a) / (b) = 8.8035556700722028905113412742298e+17

Root > 8.80355567007220289051134127423e+17 = 9.3827265067634806822605743545327e+8 MeV of proton]

 

           As per Equation -- (Ia),  Root > 1.1359046701999198466437634247209e-18 = 1.0657882858241217536767101731831e-9

 1.0657882858241217536767101731831e-9, ---- (Ib) Either 1.782662e-36 / 1.672623e-27 = 1.0657882858241217536767101731831e-9 (Source will be discuss in this article)

1.0657882858241217536767101731831e-9 * 1.672623e-27 (Proton mass)

= 1.782662e-36

1.0657882858241217536767101731831e-9 * 1.5032784196545335010226279575152e-10 (P. energy)

= 1.60217653e-19 Energy

.Proton energy x 1.0657882858241217536767101731831e-9 = 1.60217653e-19 Energy

Proton mass x 1.0657882858241217536767101731831e-9 =  = 1.782662e-36 Mass.

 Either 1.782662e-36 Mass / 1.0657882858241217536767101731831e-9

= 1.672623e-27 = Proton mass

1.60217653e-19 Energy / 1.0657882858241217536767101731831e-9

= 1.5032784196545335010226279575152e-10

1.782662e-36 / 1.60217653e-19 = 1.1126501771936454467973014184648e-17--- (Ic)

 

1/2  method, As per Pythagoras Formula (See Image bellow)

             Figure 1 (a) & (b) is same square area and value.

             And square area of is ‘C’ equal of (a) + (b)

Figure 2 , inside of (a) & (b) are 8 parts of triangle, and ‘C’ is 16 part of triangle.

In a Circle, out of Square (a), (b) & ‘C’ there are another 3 part ‘X’ ‘Y’ ‘Z’ (see Figure 2) all are 8 part of triangle total 56 numbers of equal triangles in the circle (see Figure 3)

The Circle divided 2 part A & B, 

 

 Here discus about how ‘a’ & ‘b’ and ‘C’ interact with each other and how they are convert  Nuclear Binding Energy and (Pi), relation with (a)² + (b)² = (C)² 

The calculation of the interaction and reaction  ‘a’ & ‘b’ when the main energy (1.60217653e-19 Unit) is divided by root. That means Square area of ‘a’ is 2 part & ‘b’ also 2 part.

 1^st Calculation

 [4root>1.60217653e-19 Unit (energy) = 2.0006798189311137778946643847195e-5. Unit]

                                            See figure 4 & 4A in the Image bellow.

(2.0006798189311137778946643847195e-5)² + (2.0006798189311137778946643847195e-5)²  = 8.0054394757564684245163039923373e-10

 (8.0054394757564684245163039923373e-10) / (1.5032784853336190483669927333392e-10)

                  [1.5032784853336190483669927333392e-10 Unit Energy of Proton]

= 5.3253203274440797472232884188169^{^2} = 28.359036589889120738591606070912

28.359036589889120738591606070912 / 4 = 7.0897591474722801846479015177281 Nucleus

Binding energy. Root > 7.0897591474722801846479015177281 = 2.6626601637220398736116442094084 / 2 = 1.3313300818610199368058221047042

4power >1.3313300818610199368058221047042 = 3.1415427980729295704582291307592 ( Pi )

[ Example for Image –1, {[Square (a) + Square (b)] / Proton energy}^{^2} / 4 = Binding energy ]

 

[ note: 8.0054394757564684245163039923373e-10 <4root = 0.00531919968970758718886881769835

0.00531919968970758718886881769835 / 9.109390e-31 (Electron mass) = 5.8392490492860522920511886068661e+27 Unit,

256root> = 5.8392490492860522920511886068661e+27 = 1.2836964258839194878867439878894

1.2836964258839194878867439878894 * 7 = 8.9858749811874364152072079152256 Unit (almost same digit of speed of light square for why 256 times root use hare because 16 square = 256)

    1.2836964258839194878867439878894 * 0.413334 = 0.5305953784963 Unit.

(L = 0.413334 and 1.28369..,digit/number is a constant unit, 0.53…, unit Radius of ‘H’ atom’s, and also atomic gravity this has been discussed in detail in all previous articles so follow reference article)

Or 8.9858749811874364152072079152256 / 7 (either 9.1 divided by resultant binding energy 7.089)

= 1.2836964258839194878867439878894, to the power 256> 1.2836964258839194878867439878894

= 5.8392490492860522920511886068661e+27.

0.00531919968970758718886881769835 / 5.8392490492860522920511886068661e+27

= 9.10939e-31 Unit electron mass, in this process we can calculate electron mass also, another process will be discuss in this article.]

  1/3 method – As per Rule  (a)² + (b)² = (C)²   how to convert Proton energy (1.5032784196545335010226279575152e-10) Unit to 1.60217653e-19 Unit energy

And  about 4Pi.

Here,  in this part of calculation Energy divided by 2, which is value of ‘a’ and ‘b’

Square area.

 

[ Energy root> 1.60217653e-19 / 2 = 8.01088265e-20 <root = 2.8303502698429394217655138448226e-10. Square ‘a’ & ‘b’ are quail Area and Value. ] 

(2.8303502698429394217655138448226e-10)² + (2.8303502698429394217655138448226e-10)²

= 1.60217653e-19 Unit of energy

 (a= 2.8303502698429394217655138448226e-10) & (b= 2.8303502698429394217655138448226e-10)

One part, about (a) Either (b) Square: = 2.8303502698429394217655138448226e-10

2.8303502698429394217655138448226e-10 / 1.5032784853336190483669927333392e-10 (Proton energy) = 1.8827850577631372556462700585127

4power>1.8827850577631372556462700585127 <4power = 12.566171192291718281832916523035

It is 4 Pi.

                          Rule:-1, [root>(Energy/2) / Proton Energy]^{^4} = 4Pi. 

[Note: Root > 1.60217653e-19 =  (4.0027197378782342122581519961687e-10)

 (4.0027197378782342122581519961687e-10) + (4.0027197378782342122581519961687e-10)

= root > 3.204353060000e-19  = 5.6607005396858788435310276896454e-10

(5.6607005396858788435310276896454e-10) / (1.5032784853336190483669927333392e-10)

= 3.7655701155262745112925401170256……( i ) will be discuss next step ]

 

Or 12.566171192291718281832916523035 <4root = 1.8827850577631372556462700585127

2.8303502698429394217655138448226e-10 / 1.8827850577631372556462700585127

= 1.5032784853336190483669927333392e-10 energy

So Energy 1.60217653e-19 to Proton energy Either Proton energy to 1.60217653e-19 Unit.

                          Rule:-2  [root> (1.60217653e-19 / 2)] / 4root> 4Pi = Proton Energy.

As per Image –1, ‘a’ & ‘b’ same value.

{Example: Root>[(a) or (b)]} / 1.8827850577631372556462700585127 = Proton Energy.

[ Note: About 1.8827850577631372556462700585127 Unit,

1.8827850577631372556462700585127 / 0.41333 = 4.5551618749259363115338108981025

(4.5551618749259363115338108981025)^{^2} = 20.7495 Unit (20.7495 / 4) = 5.187374926695

5.187374926695 / (root> 3) = 2.9949323103148734672251289879132, (or 3)

Cube root> 4.5551618749259363115338108981025 = 1.6576821906446909668021833608666

Root>1.6576821906446909668021833608666  = 1.287510074 x 7 = 9.012570518, (L = 0.413334 Ref..1)

 

Now  Pi = 1.60217653e-19 <root = 4.0027197378782342122581519961685e-10

4.0027197378782342122581519961685e-10 / 1.5032784196545335010226279575152e-10

= 2.6626602800551704435263034591073 /2 = 1.3313301400275852217631517295536

1.3313301400275852217631517295536 <4power = 3.1415433470961018845922239897717 = Pi

                          Rule:- 3, {[(root > Energy) / Proton energy ] / 2 }^{^4} = Pi

 

     2.              Proton energy to Mass energy according to the Pythagoras rule and here mention

                      Square area and triangles which is in this square area. 

 

(4Pi = 12.566171192291718281832916523035 <4root = 1.8827850577631372556462700585127)

Again: 1.8827850577631372556462700585127 * 2 = 3.7655701155262745112925401170254

[ Root> (1.6021766e-19 / 2) = 2.8303503316727418858431448278252e-10 ]

2.8303502698429394217655138448226e-10 * 3.7655701155262745112925401170254….( i )

= 1.0657882858241217536767101731831e-9 Source of --- (Ib)

1.0657882858241217536767101731831e-9 * 1.5032784853336190483669927333392e-10

= 1.6021766e-19 Energy, or 1.6021766e-19 / 1.0657882858241217536767101731831e-9

= 1.5032784853336190483669927333392e-10 Proton Energy.

 

So we can write here according to the value obtained from the above calculation as per Image.

  [When (a) & (b) acts, ‘C’ reacts with (a) & (b) in the opposite direction. square ‘a’ + ‘b’ = square ‘C’ = 1.6021766e-19 Unit. (See Image)]

Root [(square ‘a’ + ‘b’ or square ‘C’) / 2] x 2(4root > 4pi) = 1.0657882858241217536767101731831e-9 ---- (iA)

Example: 1.6021766e-19 /2  =8.010883e-20, root> 8.010883e-20 = 2.8303503316727418858431448278252e-10  * 2(4root>12.566171192291718281832916523035)

Or 2.8303503316727418858431448278252e-10 * 2 * 1.8827850577631372556462700585127

= 1.0657882625416756043027438806527e-9 Unit, same way for next calculation.

Or (Square ‘a’ + ‘b’ either ‘C’) / [(square ‘a’ + ‘b’ or square ‘C’) / 2] x (4root > 4pi) = Proton Energy.

---- ( iiA)

          

   [(Square ‘a’ + ‘b’ either ‘C’) / (X/Y)]^{^2} / [(a + b) or ‘C’] = Mass / Energy = 1.782662e-36 / 1.6021766e-19  = 1.112650128581331171607424549828e-17 Unit. ---- (iiiA)

Proton Mass 1.672623e-27 / 1.5032784853336190483669927333392e-10 (Proton energy)

= 1.1126501285813311716074245498281e-17 Unit.  ---- (ivA)

As per mention calculation : (iiA) x (iiiA) = (iiA) x (ivA) = (1.5032784853336190483669927333392e-10 ) x (1.112650128581331171607424549828e-17) = 1.672623e-27 Unit = Proton Mass,

So as per figure 1&2 square ‘a’ + ‘b’ = square ‘C’ = 1.6021766e-19 Unit.

[(Square ‘a’ + ‘b’ either ‘C’) / (X/Y)]^{^2} / [(a + b) or ‘C’] x (Square ‘a’ + ‘b’ either ‘C’) / [(square ‘a’ + ‘b’ or square ‘C’) / 2] x (4root > 4pi) = Proton mass. = 1.672623e-27 Unit ….(1m)

Proton Mass 1.672623e-27 * 1.0657882858241217536767101731831e-9--(iA) = 1.782662e-36 Mass.

So (iA) x (1m) = Mass.

Hence, as per Image square ‘a’ + ‘b’ = square ‘C’ = 1.6021766e-19 Unit. we can write:-

Root [(square ‘a’ + ‘b’ or square ‘C’) / 2] x 2(4root > 4pi) x [(Square ‘a’ + ‘b’ either ‘C’) / (X/Y)]^{^2} / [(a + b) or ‘C’] x (Square ‘a’ + ‘b’ either ‘C’) / [(square ‘a’ + ‘b’ or square ‘C’) / 2] x (4root > 4pi) = Mass

Same process we can calculate energy also

For example 1.6021766e-19 / 1.5032784853336190483669927333392e-10 = 1.0657882858241217536767101731831e-9 = (iA)

Or {[(Square ‘a’ + ‘b’ either ‘C’) / (X/Y)]^{^2} / [(a + b) or ‘C’] x (Square ‘a’ + ‘b’ either ‘C’) / [(square ‘a’ + ‘b’ or square ‘C’) / 2] x (4root > 4pi) = Proton mass} / {Root [(square ‘a’ + ‘b’ or square ‘C’) / 2] x 2(4root > 4pi) = (iA)} = 1.5032784853336190483669927333392e-10 Unit Proton energy.

We know 1.672623e-27 Unit Proton mass,

1.672623e-27 * 1.0657882858241217536767101731831e-9 = 1.782662e-36 Mass.

So,   Rule: 4,    {[4root> (4Pi)] x 2} x [root>(Energy / 2)] x Proton energy = Energy.

         Rule: 5,    {[4root> (4Pi)] x 2} x [root>(Energy / 2)] x Proton mass = Mass.

 

 [Note: 12.566171192291718281832916523035 * 3600 Sec. = 4.5238216292250185814598499482926e+4 <4power = 4.188146751069289804378863809097e+18

4.188146751069289804378863809097e+18 = (4/3)xPi x 10^{^18}

4.188146751069289804378863809097e+18 / Pi = 1.3331285156538783196105425004912e+18

Sqr> 1.3331285156538783196105425004912e+18 = 1.7772316392495128918537526609051e+36

1.7772316392495128918537526609051e+36 * 1.782662e-36 (Mass) = 3.1682033084878151508177944259945,  (3.1682033084878151508177944259945)^{^2} = 10 ]

 

 2/1     Here we can see how  Root> 3, Time 3600 Second, and Mass etc act and react and also how to involve each other,  (see Figure 4 & 4A in image bellow.)

Time part = ‘Y’= 3600. root3 Cube = 5.1961524227066318805823390245176 * 4 = 20.78460969082652752232935609807

square>20.78460969082652752232935609807 = 432. (X/Y = (432 / 3600) = 0.12 & Y/X = (3600 / 432) = 8.33333)

  [(Root 3) Cube x 4]^{^2} = part ‘X’ = (5.1961524227066318805823390245176 x 4)^{^2}

 

Example:

C = 1.60217653e-19 Unit, X = 432 Unit = [( root 3)Cube] Square

Y = 3600 = (450 x 8)

[1.60217653e-19 / (432 / 3600)]^{^2} or (1.60217653e-19 / 0.12)^{^2} = (1.335147108333…333e-18)^{^2}

= 1.7826178008908617361111111111111e-36 Mass…1

[‘C’ x (Y/X) ]^{^2} = Mass, and [Square (‘a’ + ‘b’) x (Y/X) ]^{^2} = Mass.

or [‘C’ / (X/Y)]^{^2} = Mass

In this way each force either energy is always bound by a chain of interactions and  reactions. 

 

square> 5.1961524227066318805823390245176  = 27 (Note:> 6cube = 216 x 2 = 432)

1.60217653e-19 / 432 = 3.7087419675925925925925925925926e-22

3.7087419675925925925925925925926e-22 * 3600 = 1.3351471083333333333333333333333e-18

1.3351471083333333333333333333333e-18 <sqr = 1.782617800890861736111…111e-36 Mass…2

432 / 1.60217653e-19 = 2.6963320951905343414311530328059e+21

3600 / 2.6963320951905343414311530328059e+21 = 1.782617800890861736111...1112e-36 Mass-3

So As per Pythagoras Rule

 {Energy / [(root 3 Cube x 4)^{^2} / Time]}^{^2} Either [Energy / (X/Y)]^{^2} = Mass.

Or {[(a) + (b)] / (X/Y)}^{^2} = Mass or [(C) / (X/Y)]^{^2} = Mass, or [(C) x (Y/X)]^{^2} = Mass

Or {[(a) + (b)] x (Y/X)}^{^2} = Mass.

Same process for next calculation.

Energy 1.60217653e-19 * 8.33333333 = 1.33514710779927449e-18 Unit

(1.33514710779927449e-18)^{^2} = 1.7826177994647674956836405703648e-36 Unit  Mass--3

Energy 1.60217653e-19 / 0.12 = 1.3351471083333333333333333333333e-18

(1.335147108333333e-18)^{^2} = 1.782617800890861736111…11e-36 Unit Mass.---4 

1.7826177994647674956836405703648e-36 * (0.12)^{^2} = 2.5669696312292651937844424213253e-38

Root > 2.5669696312292651937844424213253e-38 = 1.602176529359129388e-19 Unit Energy …1

1.7826177994647674956836405703648e-36 * (8.33333333)^{^2} = 1.2379290264157453169423926539807e-34

Root > 1.2379290264157453169423926539807e-34 = 1.11262258938767970573357517e-17

                           Source of  1.11262258938767970573357517e-17 Unit ---- (Ic)

[Note,  Square> 1.11262258938767970573357517e-17  = 1.2379290264157453169423926539807e-34

 9.109390e-31 / 1.2379290264157453169423926539807e-34 = 7.3585721035841582315010320383631e+3

36root> 7.3585721035841582315010320383631e+3 = 1.2805924350038939741757184924912e+0

1.2805924350038939741757184924912 * 7.0897591474722801846479015177281= 9.07909193 Unit.

Here  this calculation if we calculate from back we can get Electron mass 9.109390e-31. Unit.]

 

 1.60217653e-19 * 1.11262258938767970573357517e-17 = 1.7826178e-36 Unit Mass – 5

1.7826177994647674956836405703648e-36 / (8.33333333)^{^2} = 2.5669696332828409000000000000001e-38 .

Root> 2.5669696332828409000000000000001e-38 = 1.60217653e-19 Unit  Energy

Proton Energy>1.5032784853336190483669927333392e-10 * 1.11262258938767970573357517e-17

= 1.6725816009226803151635517068013e-27  PROTON MASS

 

 2/2       Activity of : Space 360 Degree & Time 3600 sec. in a Mass Now Function of 360 Degree

[root3 cube = 5.1961524227066318805823390245176 * 4 = 20.78460969082652752232935609807

 360 / 20.78460969082652752232935609807 = 17.320508075688772935274463415059

10 times of root> 3,

17.320508075688772935274463415059 * 3600 = 6.2353829072479582566988068294212e+4 ---- (1)

(9/7)^{^4} = 2.7326114119117034568929612661391 * 1.782617800890861736111111111111e-36 (Resultant Mass Value) = 4.8712017457913135571116201582671e-36 * 3 =

1.4613605237373940671334860474801e-35 * 6.2353829072479582566988068294212e+4 ---- (1)

= 9.1121424310390711308017289368858e-31 Electron Mass.

9.1121424310390711308017289368858e-31 * 1838 = 1.6748117788249812738413577785996e-27

Neutron mass Value. (Neutron Mass heavier than electron mass 1838 times)

 

 Maximum 32 numbers of electrons can stay in one orbit so for one electron’s acquire place 360 / 32 = 11.25 Degree, (With induction area) this has been discussed in detail in reference 1, 2, 3 . 

 

In 360 Degree energy = 1.60217653e-19 Unit  (Unitary Process )

In 1 degree energy = (1.60217653e-19/360) unit = 4.4504903611111e-22 Unit.

In 3.75 ,, ,, ,, ,, ,, ,, ,, = 3.75 * 4.4504903611111e-22 = 1.6689338854166625e-21 Unit

Acquire Place of Energy per Electron 11.25 Degree Angle. (Minimum angle for one electron With induction area reference  “Atomic Mass Energy Primary Colour )  =

(3.75 *3)  = 11.25 * 4.4504903611111e-22 = 5.0068016562499875e-21 ------------ [1S]

 

 In one energy 1.60217653e-19 space is = 360 (Unitary Process)

,, ,, ,, ,, ,, ,, ,,, ,,,,,,,,, ,,, ,,,,,,,,,,, 360 / 1.60217653e-19 = 2.246943412658778617859294194005e+21

In 11.25 * 2.246943412658778617859294194005e+21 

= 2.5278113392411259450917059682556e+22 ---------- [2S]

 

Time in 360 Degree is 3600 Sec.

In 1 Degree = 3600 / 360 = 10 sec. in 3.75 * 10 = 37.5 and with induction area= 37.5 * 3 = 1.125e+2 Sec.  --- [3S]

 

[1S] x [2S] = 5.0068016562499875e-21 * 1.125e+2 = 5.6326518632812359375e-19 * (0.533333333)^{^2} = 1.60217653e-19 Unit Energy .

[0.5333.., Unit Radius of ‘H’ Atom’s & 0.5333.., Unit Atomic Gravity Reference --1]

 

[1S] / [2S] = 5.0068016562499875e-21 / 2.5278113392411259450917059682556e+22

= 1.9806864454342858729119444444444e-43 < root 32 = 0.04629408359682655552521135035531

0.04629408359682655552521135035531 * 360 = 16.665870094857559989076086127912

 (16.665870094857559989076086127912 * 1.60217653e-19)/2 = 1.3350832959004828153782380789199e-18 <sqr = 1.782447407e-36 Unit Mass

 

 2/3    Some clue have been made in favor of the information given in previous article about rule  “E = m – (m/10)”

 

4.005441325e-20 / 2 = 2.0027206625e-20 * (5.1961524227066318805823390245176 * 2) =

2.0812883644908011686046965793963e-19 sqr = 4.33176125616479401875e-38

2.0812883644908011686046965793963e-19 / 1.2990381056766579701455847561294

=  = 1.60217653e-19 Unit Energy

4.33176125616479401875e-38 / 3 = 1.44392041872159800625e-38

1.44392041872159800625e-38 / 9 = 1.6043560208017755625e-39 …..(1A)

1.6043560208017755625e-39 / 9 =

1.7826178008908617361111111111111e-40

 [ Source of 1.299..Unit : 90, 900 etc.  -- 

3 Cube = 27, 27 /16 = 1.6875 <root = 1.2990381056766579701455847561294

4power>1.5 = 5.0625 / 3 = 1.6875 < root = 1.2990381056766579701455847561294

3600 Sec./4 = 450 x 2 = 900, 360 Degree / 4 = 45 x 2 = 90 ]

 

8.01088265e-20 * 90* = 7.209794385e-18, square> 7.209794385e-18 = 5.1981135073977528225e-35

5.1981135073977528225e-35 / 900 = 5.775681674886392025e-38 <root

= 2.403264795e-19 / 2 = 1.2016323975e-19

1.2016323975e-19 / 90 = 1.3351471083333333333333333333333e-21

1.3351471083333333333333333333333e-21 <square = 1.7826178008908617361111111…..11e-42

1.7826178008908617361111111111111e-42 * 900* = 1.6043560208017755625e-39 ---- (1B)

1.6043560208017755625e-39 * 8 = 1.28348481664142045e-38 * 2 = 2.5669696332828409e-38

 Root >2.5669696332828409e-38 = 1.60217653e-19 Energy.

 [ Note: 0.53033008588991064330063327157864 <sqr = 0.28125 * 2 = 0.5625 * 16 = 9

0.53 Unit is atomic gravity and radius of H atom’s reference-1. ]

 

  Here use equation--- (Ic) = 1.11262258938767970573357517e-17  Unit.

1.11262258938767970573357517e-17 * 360 = 4.005441321795646940640870612e-15

4.005441321795646940640870612e-15 * 4 = 1.6021765287182587762563482448e-14

(Note: energy Digit or number Same but power is different)

1.11262258938767970573357517e-17 * 360 * 3600 = 1.44195887584643289863071342032e-11 Unit 

1.44195887584643289863071342032e-11 / 9 = 1.6021765287182587762563482448e-12              

(Note: energy Digit or number Same but power is different  )

4.005441321795646940640870612e-15  Sqr = 1.604356018234805930757340879559e-29

 

(1.60217653e-19 * 3)= (4.80652959e-19 /4)= (1.2016323975e-19 - 1.60217653e-19)= -4.005441325e-20

( -4.005441325e-20 )^{^2}  = 1.6043560208017755625e-39 --- (1C) or (1.2016323975e-19 )^{^2} =  1.44392041872159800625e-38 / 9 = 1.6043560208017755625e-39 ----- (1D)

1.6043560208017755625e-39 * 8 = 1.28348481664142045e-38 * 2 = root > 2.5669696332828409e-38

 = 1.60217653e-19 Unit or 1.6043560208017755625e-39 x 16 = 1.60217653e-19 Unit Energy.

 1.2016323975e-19 / 9 = (1.335147108333..,e-20)^{^2}  = 1.7826178008908617361e-40 * 9 = 1.60435602080177556249e-39,

1.60217653e-19 / 12 = (1.3351471083333333333333333333333e-20)^{^2}  = 1.7826178008908617361111111111111e-40 Unit mass

 

As per (1A, 1B, 1C, 1D) if we take only Digit without any power then

  1.6043560208017755625 * (10/9) = 1.7826178008908617361111111111111 Unit either

Mass Number of Digit = 1.782662, and it’s equivalent energy = 1.60217653 unit.

Then 1.782662 – (1.782662 /10) = 1.6043958 Unit.

(1.7826178008908617361111111111111) – (1.7826178008908617361111111111111 /10) = 1.6043560208017755625 Unit Energy.

So as per  Energy = mass – (mass/10) = 1.6043560208017755625 x (10/9) =1.7826178008908617361111111111111 Unit Mass.

Almost same Digit/Number of mass digit 1.782662 .

1.7826178008908617361111111111111 / (10)^{^36} = 1.782617800890861736111…111e-36 Unit. Mass

(1.6043560208017755625 / (10)^{^35} ) / 9 = 1.7826178008908617361111111111111e-36 Unit Mass

so Here is make sure that E=m-(m/10) is a Useful formula.

 

 

                                                                Conclusion:

1) The amount of Pi, 4Pi, (4/3) Pi, root> 3. Is hidden inside the Pythagoras formula (a)^{^2} + (b)^{^2} = C^{^2},

2) 2 Numbers of 1.60217653e-19 Unit Energy present in a Neutron.

3) when create a nucleus of atom then Time & Space also act one type of energy,

4) In a Neutron 4 type of energy.

5) The size either shape of Neutron is never round, they are bound to be hexagonal, pentagonal etc. because if the neutron in round in shape then when they are connected to each other a space will be created between them so they are hexagonal, pentagonal etc. shaped.

6) (Energy x 8.33333)^{^2} = Mass. (Energy / 0.12)^{^2} = Mass.

7) Energy x 1.11262258938768e-17 = Mass

8) Mass x 1.0657882858241217536767101731831e-9 = Energy

9) [root>(Energy/2) / Proton Energy]^{^4} = 4Pi

10) [root> (1.60217653e-19 / 2)] / 4root> 4Pi = Proton Energy.

11) {[(root > Energy) / Proton energy ] / 2 }^{^4} = Pi

12) {[4root> (4Pi)] x 2} x [root>(Energy / 2)] x Proton energy = Energy.

13) {[4root> (4Pi)] x 2} x [root>(Energy / 2)] x Proton mass = Mass.

14) Each force either energy is always bound by a chain of interactions and  reactions. 

15) in a Atom’s Each energy (Time, space, energy, etc.) follows Pythagoras formula (a)^{^2} + (b)^{^2} = C^{^2},

 

Reference:

1) Atomic Mass Energy Primary Colour (Mendeley Data)

2) Atomic Time – Space (Mendeley Data)

3) Atomic Mass Energy and Constant. (Mendeley Data)

4) Energy to Energy to Mass Conversion. (Mendeley Data)